Example

Let’s look at a standard deck of 52 cards.

What is the probability of getting 2 kings assuming that the first one is not replaced?

4/52 * 3/51 = 1/13*1/17= 1/221

What is the probability of getting 2 kings assuming that the first one is replaced?

4/52 * 4/52 = 1/13 * 1/13 = 1/169

Instructions

Now for your main post do a similar problem using with replacement and without replacement. You can use a card problem as long as it is not 2 kings. Try your best to be original.

**MODEL ANSWER**

Finding a Conditional Probability

- If you draw two cards from a deck without replacement, what is the probability that the two cards are both aces? What is the probability that the second card will be a Jack if the first card is a Queen?
- A container has 6 green, 4 yellow, and 5 orange candies. A boy draws two candies without replacement. What is the probability that the two candies are green?
- Assume that 3 cards are drawn from a deck one at a time without replacement. xxxxx is the xxx that all 3 cards are Black? You do not draw any spade?
- A bag xxx 11 xxx and 10 pink xxx. Two balls are xxx with replacement. xxx is the probability of xxx two pink xxx?
- Without xxx, 3 cards are xxx from a xxx one at a time. Find the probability the xxx is a Club, a Heart and a Diamond (in that order).