Genetic Problems
1. Guinea pigs
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Write My Essay For MeA. Ss
B. SS
C. ss
Cross SS X ss
| S | S | |
| s | sS | sS |
| s | sS | sS |
100% of the offspring will have short hair
2. Ss X Ss
| S | s | |
| S | SS | Ss |
| s | sS | ss |
75% of the offspring will have short hair
25% of the spring will have long hair
3. Probable genotype
| S | s | |
| S | SS | Ss |
| s | Ss | ss |
75% short
25% long
4. XhY X Xhx
| Xh | X | |
| Xh | XhXh | XhX |
| Y | XhY | XY |
There is 25% chance that the male child will be normal.
5. RR X R’R’
| R’ | R’ | |
| R | RR’ | RR’ |
| R | RR’ | RR’ |
Genotypes = 100 percent RR’
Phenotypes = 100 percent Roan
RR’ X R’R’
| R’ | R’ | |
| R | RR’ | RR’ |
| R’ | R’R’ | R’R’ |
Genotypes = 50 % RR’: 50% R’R’
Phenotypes = 50% Roan and 50% white
6.
Round fruit = R (dominant)
Long fruit = r (recessive)
Smooth skin = S (dominant)
Fuzzy skin = r (recessive)
Round smooth = RRSS
Long-fuzzy = rrss
Parent generation RRSS × rrss
First generation RrSs (Round-smooth)
Upon self-crossing RrSs × RrSs
Round smooth (583) Long fuzzy (602) Round-fuzzy (21) Long-smooth (16)
The most probable cause of the unusual phenotype above is as a result of the crossing over of chromosome leading to the swapping of alleles of unlinked genes.
7. (1) Homozygous recessive (mm) are albinos
(2) BBMM X BbMm
| BM | |
| BM | BBMM |
| Bm | BBMm |
| bM | BbMM |
| bm | BbMm |
First generation (F1) Phenotypes = 100% brown
(3) BbMm x BbMm?
| BM | Bm | bM | bm | |
| BM | BBMM | BBMm | BbMM | BbMm |
| Bm | BBMm | BBmm | BbMm | Bbmm |
| bM | BbMM | BbMm | bbMM | bbMm |
| bm | BbMm | BbMm | bbMm | bbmm |
9 brown: 3 blond: 4 albinos
(4) BbMm X bbmm
| bm | bm | bm | bm | |
| BM | BbMm | BbMm | BbMm | BbMm |
| Bm | Bbmm | Bbmm | Bbmm | Bbmm |
| bM | bbM | bbMm | bbMm | bbMm |
| bm | bbmm | bbmm | bbmm | bbmm |
1brown: I blond: 2 albinos
8. (1) XY X XCXC
| XC | XC | |
| X | XXC | XXC |
| Y | XCY | XCY |
Probability of having a color blind son is one (all males will be color blind)
Probability of having a color blind daughter is zero (all daughters will be carriers)
(2) The case will stand up in court because the probability of having a color blind daughter is zero
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